Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 32768/32768 K (Java/Others) Total Submission(s): 2696 Accepted Submission(s): 1048
水题:给你身份证号让你找信息;注意string不能用scanf输入。。。
代码:
#include<iostream> #include<cstdio> #include<algorithm> #include<cstring> #include<cmath> #include<queue> #include<stack> #include<vector> #include<map> #include<string> using namespace std; const int INF=0x3f3f3f3f; const double PI=acos(-1.0); #define mem(x,y) memset(x,y,sizeof(x)) #define SI(x) scanf("%d",&x) #define SL(x) scanf("%lld",&x) #define PI(x) printf("%d",x) #define PL(x) printf("%lld",x) #define P_ printf(" ") #define T_T while(T--) typedef long long LL; map<string,string>mp; int main(){ int T,y,m,d; string s; SI(T); mp["33"]="Zhejiang"; mp["11"]="Beijing"; mp["71"]="Taiwan"; mp["81"]="Hong Kong"; mp["82"]="Macao"; mp["54"]="Tibet"; mp["21"]="Liaoning"; mp["31"]="Shanghai"; T_T{ //scanf("%s",s.c_str()); cin>>s; printf("He/She is from %s,and his/her birthday is on %s,%s,%s based on the table.\n",mp[s.substr(0,2)].c_str(),s.substr(10,2).c_str(),s.substr(12,2).c_str(),s.substr(6,4).c_str()); //cout<<"He/She is from "<<mp[s.substr(0,2)]<<",and his/her birthday is on "<<s.substr(10,2)<<","<<s.substr(12,2)<<","<<s.substr(6,4)<<" based on the table."<<endl; } return 0; }
原文:http://www.cnblogs.com/handsomecui/p/5084243.html