简单版本号比较:
public class CompareVersion {
public static void main(String[] args) {
// TODO Auto-generated method stub
java.lang.System.out.println
( value( "10.1.2.0" ) > value( "9.0.0.0" ));
}
public static long value(final java.lang.String string) {
if (string.contains(".")) {
final int index = string.lastIndexOf(".");
return value(string.substring(0, index)) * 100
+ value(string.substring(index + 1));
} else
return java.lang.Long.valueOf(string);
}
}
上边的简单版本号递归算法并不算好
下面我们看一个复杂点,但非常实用的版本号比较类:
public class Scratch
{
private static class VersionStringComparator
implements Comparator<String>
{
public int compare(String s1, String s2){
if( s1 == null && s2 == null )
return 0;
else if( s1 == null )
return -1;
else if( s2 == null )
return 1;
String[]
arr1 = s1.split("[^a-zA-Z0-9]+"),
arr2 = s2.split("[^a-zA-Z0-9]+")
;
int i1, i2, i3;
for(int ii = 0, max = Math.min(arr1.length, arr2.length);
ii <= max; ii++){
if( ii == arr1.length )
return ii == arr2.length ? 0 : -1;
else if( ii == arr2.length )
return 1;
try{
i1 = Integer.parseInt(arr1[ii]);
}
catch (Exception x){
i1 = Integer.MAX_VALUE;
}
try{
i2 = Integer.parseInt(arr2[ii]);
}
catch (Exception x){
i2 = Integer.MAX_VALUE;
}
if( i1 != i2 ){
return i1 - i2;
}
i3 = arr1[ii].compareTo(arr2[ii]);
if( i3 != 0 )
return i3;
}
return 0;
}
}
public static void main(String[] ss){
String[] data = new String[]{
"2.0",
"1.5.1",
"10.1.2.0",
"9.0.0.0",
"2.0.0.16",
"1.6.0_07",
"1.6.0_07-b06",
"1.6.0_6",
"1.6.0_07-b07",
"1.6.0_08-a06",
"5.10",
"Generic_127127-11",
"Generic_127127-13"
};
List<String> list = Arrays.asList(data);
Collections.sort(list, new VersionStringComparator());
for(String s: list)
System.out.println(s);
}
}
</code>
<output>
1.5.1
1.6.0_6
1.6.0_07
1.6.0_07-b06
1.6.0_07-b07
1.6.0_08-a06
2.0
2.0.0.16
5.10
9.0.0.0
10.1.2.0
Generic_127127-11
Generic_127127-13
</output>
如果简单的比较版本号,抽取其中的compare()方法即可!
欢迎转载!
JAVA 软件升级版本号比较
原文:http://www.cnblogs.com/wvqusrtg/p/5104563.html