一个整数对应二进制中1的个数

#include <stdio.h>
#include <stdlib.h>

/*
	4.统计一个整数对应的二进制数的1的个数。
	  输入一个整数（可正可负）,
	  输出该整数的二进制包含1的个数,
	  “ctl+ z” 结束。
*/

int main(){
	int number;
	while (scanf("%d", &number) != EOF){
		int num[100] = {0};
		int length = 0;
		if (number < 0)
			number = -number;
		do{
			num[length++] = number % 2;
			number /= 2;
		} while (number != 0);
		int count = 0;
		for (int i = 0; i < length; ++i)
			if (num[i] == 1)
				count++;
		printf("The binary form of this number is: ");
		for (int i = length - 1; i >= 0; --i)
			printf("%d",num[i]);
		printf("\n");
		printf("The number of 1 is: %d.\n",count);
	}
	system("pause");
	return 0;
}