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对大数据的切片

时间:2016-01-07 16:12:10      阅读:202      评论:0      收藏:0      [点我收藏+]

常常会用到切片技术

java代码

 1 @Transactional(readOnly=false)
 2     public void saveCommonMsg(CommonMsg commonMsg) {
 3 
 4         //删除碎片
 5         List<CommonMsgContent> list= commonMsgContentDao.findCollectionByConditionNoPage("", null, null);
 6     
 7         commonMsgContentDao.deleteObjectByCollection(list);
 8         //进行切片
 9         
10         String station = commonMsg.getStationRun();
11         
12         String dev = commonMsg.getDevRun();
13         
14         List<String> station_list = StringUtils.getContentByList(station, 30);//调用字符拆分,本博客中有
15         
16         List<String> dev_list = StringUtils.getContentByList(dev, 30);
17         //保存
18         for (int i = 0; i < station_list.size(); i++) {
19                 CommonMsgContent commonMsgContent = new CommonMsgContent();
20                 
21                 commonMsgContent.setContent(station_list.get(i));
22                 commonMsgContent.setType("1");//设置常量,在数据库中便于查找
23                 
24                 commonMsgContent.setOrderby(i+1);//设置拆分字符的存放顺序,避免拼接字符串错误
25                 
26                 commonMsgContentDao.save(commonMsgContent);
27         }
28         for (int i = 0; i < dev_list.size(); i++) {
29             CommonMsgContent commonMsgContent = new CommonMsgContent();
30             
31             commonMsgContent.setContent(dev_list.get(i));
32             commonMsgContent.setType("2");
33             
34             commonMsgContent.setOrderby(i+1);
35             
36             commonMsgContentDao.save(commonMsgContent);
37             
38         }
39         
40         commonMsgDao.saveMsg(commonMsg);
41     }

拼接字符串

 

 1 public CommonMsg findcommonMsg() {
 2         
 3         //查询所有的切片
 4         String condition = " and  o.type = ?";
 5         Object[] params = new Object[]{"1"};
 6         Map<String, String> orderby = new HashMap<String, String>();
 7         orderby.put(" o.orderby ", "asc");
 8         List<CommonMsgContent> list = commonMsgContentDao.findCollectionByConditionNoPage(condition, params, orderby);
 9         
10         String station_msg = "";
11         
12         for (CommonMsgContent commonMsgContent : list) {
13             station_msg += commonMsgContent.getContent();//拼接字符串
14         }
15         condition = " and o.type = ? ";
16         params = new Object[]{"2"};
17         orderby = new HashMap<String, String>();
18         orderby.put("  o.orderby ", "asc");
19         list = commonMsgContentDao.findCollectionByConditionNoPage(condition, params, orderby);
20         
21         String dev_msg = "";
22         
23         for (CommonMsgContent commonMsgContent : list) {
24             dev_msg += commonMsgContent.getContent();//拼接字符串
25         }
26         
27         CommonMsg Msg = commonMsgDao.findMsg();
28         
29         if (Msg != null) {
30             //将拼接好的字符串放入到CommonMsg中
31     Msg.setDevRun(dev_msg);
32      Msg.setStationRun(station_msg);
33     return Msg;
34     }
35     return null;
36   }

 

对大数据的切片

原文:http://www.cnblogs.com/pi-qingwen/p/5110000.html

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