Given a collection of intervals, merge all overlapping intervals.
For example,
Given [1,3],[2,6],[8,10],[15,18],
return
[1,6],[8,10],[15,18].
这里主要注意的是STL的sort的函数的comparor要写成static函数,而且参数采用值传递,不要用引用。
class Solution { public: static bool comp(Interval m1, Interval m2) { return m1.start < m2.start; } vector<Interval> merge(vector<Interval> &intervals) { sort(intervals.begin(), intervals.end(), Solution::comp); vector<Interval> ret; if (intervals.empty()) return ret; Interval pre(intervals[0]); for (int i = 0; i < intervals.size(); ++i) { if (intervals[i].start <= pre.end) { if (intervals[i].end > pre.end) pre.end = intervals[i].end; } else { ret.push_back(pre); pre = intervals[i]; } } ret.push_back(pre); return ret; } };
Leetcode | Merge Intervals,布布扣,bubuko.com
原文:http://www.cnblogs.com/linyx/p/3662939.html