首页 > Windows开发 > 详细

C# post请求 HttpWebRequest

时间:2016-01-11 18:03:27      阅读:286      评论:0      收藏:0      [点我收藏+]

//body是要传递的参数,格式"roleId=1&uid=2"
//post的cotentType填写:
//"application/x-www-form-urlencoded"
//soap填写:"text/xml; charset=utf-8"

        public  string PostHttp(string url, string body, string contentType)
        {
            HttpWebRequest httpWebRequest = (HttpWebRequest)WebRequest.Create(url);
 
            httpWebRequest.ContentType = contentType;
            httpWebRequest.Method = "POST";
            httpWebRequest.Timeout = 20000;
 
            byte[] btBodys = Encoding.UTF8.GetBytes(body);
            httpWebRequest.ContentLength = btBodys.Length;
            httpWebRequest.GetRequestStream().Write(btBodys, 0, btBodys.Length);
 
            HttpWebResponse httpWebResponse = (HttpWebResponse)httpWebRequest.GetResponse();
            StreamReader streamReader = new StreamReader(httpWebResponse.GetResponseStream());
            string responseContent = streamReader.ReadToEnd();
 
            httpWebResponse.Close();
            streamReader.Close();
            httpWebRequest.Abort();
            httpWebResponse.Close();
 
            return responseContent;
        }

C# post请求 HttpWebRequest

原文:http://www.cnblogs.com/su-king/p/5121986.html

(0)
(0)
   
举报
评论 一句话评论(0
关于我们 - 联系我们 - 留言反馈 - 联系我们:wmxa8@hotmail.com
© 2014 bubuko.com 版权所有
打开技术之扣,分享程序人生!