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*Find Peak Element

时间:2016-01-12 07:41:39      阅读:257      评论:0      收藏:0      [点我收藏+]

A peak element is an element that is greater than its neighbors.

Given an input array where num[i] ≠ num[i+1], find a peak element and return its index.

The array may contain multiple peaks, in that case return the index to any one of the peaks is fine.

You may imagine that num[-1] = num[n] = -∞.

For example, in array [1, 2, 3, 1], 3 is a peak element and your function should return the index number 2.

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Note:

Your solution should be in logarithmic complexity.

 

public class Solution {
    public int findPeakElement(int[] A) 
    {
        // write your code here
        int start = 0, end = A.length-1; // 1.答案在之间,2.不会出界 
        while(start + 1 <  end) {
            int mid = (start + end) / 2;
            if(A[mid] < A[mid - 1]) {
                end = mid;
            } else if(A[mid] < A[mid + 1]) {
                start = mid;
            } else {
                end = mid;
            }
        }
        if(A[start] < A[end]) {
            return end;
        } else { 
            return start;
        }
    }
}

 

*Find Peak Element

原文:http://www.cnblogs.com/hygeia/p/5123139.html

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