sqlserver中比较一个字符串中是否含含另一个字符串中的一个字符

USE [Fly]
GO
--参数：@inStr 待搜索字串，@fndStr 搜索字串，@doc 分隔符
-- 例：select dbo.fSearch(‘1,2,3,4,5,6‘,‘3,6,5,8,2‘,‘,‘) 返回0-不匹配，返回1-匹配(@instr中有@fndStr内容)
--可以用于表搜索，如：
-- Select *,dbo.fSearch(str,‘3,6,5,8,2‘,‘,‘) as 是否匹配 from 表名
-- @fndStr和@doc两个参数就需要你自己提供了，@inStr可以是数据表里的某个待搜索字段名
CREATE FUNCTION CGF_FN_Search(@inStr VARCHAR(500),@fndStr VARCHAR(500),@doc VARCHAR(5))
RETURNS INT
AS
BEGIN
DECLARE @i INT,@c VARCHAR(500),@fStr VARCHAR(500)
SET @fStr = @fndStr
WHILE(LEN(@fStr) > 0)
BEGIN
SET @i = Charindex(@doc, @fStr)
IF(@i = 0)
BEGIN
IF(CHARINDEX(@fStr,@inStr) > 0)
RETURN 1
ELSE
RETURN 0
END
ELSE
BEGIN
SET @c = SUBSTRING(@fStr,1,@i-1)
IF(CHARINDEX(@c,@inStr) > 0)
RETURN 1
ELSE
SET @fStr = SUBSTRING(@fStr,@i+LEN(@doc),LEN(@fStr))
END
END
RETURN 0
END

USE [Fly]
GO
/****** Object: UserDefinedFunction [dbo].[CGF_FN_SearchChar] Script Date: 09/03/2010 16:42:12 ******/
SET ANSI_NULLS ON
GO
SET QUOTED_IDENTIFIER ON
GO
CREATE FUNCTION [dbo].[CGF_FN_SearchChar](@inStr VARCHAR(500),@fndStr VARCHAR(500))
RETURNS INT
AS
BEGIN
DECLARE @i INT,@f INT,@c VARCHAR(1)
SET @i = 1
SET @f = LEN(@fndStr)
WHILE(@i <= @f)
BEGIN
SET @c = SUBSTRING(@fndStr, @i, @i)
IF(CHARINDEX(@c,@inStr) > 0)
BEGIN
RETURN 1
END
SET @i = @i + 1
END
RETURN 0
END