首页 > 编程语言 > 详细

【Java】List集合按数量分组

时间:2016-01-18 17:20:17      阅读:1265      评论:0      收藏:0      [点我收藏+]

有时候,我们需要将大的集合按指定的数量分割成若干个小集合。(比如:集合作为SQL中IN的参数,而SQL又有长度限制,所以需要分批分几次进行查询)

虽然此需求感觉不常见,但偶也写过几次类似的方法,故记录之。

 

工具类

技术分享
import java.util.ArrayList;
import java.util.List;

public class CollectionGroupUtil {
    
    public static List groupListByQuantity(List list, int quantity) {
        if (list == null || list.size() == 0) {
            return list;
        }
        
        if (quantity <= 0) {
            new IllegalArgumentException("Wrong quantity.");
        }
        
        List wrapList = new ArrayList();
        int count = 0;
        while (count < list.size()) {
            wrapList.add(list.subList(count, (count + quantity) > list.size() ? list.size() : count + quantity));
            count += quantity;
        }
        
        return wrapList;
    }
    
}
View Code

 

测试类

技术分享
import java.util.ArrayList;
import java.util.List;

import org.junit.Test;


public class CollectionGroupUtilTest {
    
    /**
     * 大于分组数量的情况
     */
    @Test
    public void test() {
        List<String> allList = new ArrayList<String>();
        for (int i = 1; i <= 504; i++) {
            allList.add(i  + "");
        }
        
        List<List<String>> groupList = CollectionGroupUtil.groupListByQuantity(allList, 50);
        int i = 0;
        List<String> list = null;
        for (int c = 0; c < groupList.size(); c++) {
            list = groupList.get(c);
            
            System.out.println("第" + (c + 1) + "组: ");
            for (String temp : list) {
                System.out.print(temp + ", ");
            }
            System.out.println();
        }
    }

    /**
     * 小于分组数量的情况
     */
    @Test
    public void test2() {
        List<String> allList = new ArrayList<String>();
        for (int i = 1; i <= 45; i++) {
            allList.add(i  + "");
        }
        
        List<List<String>> groupList = CollectionGroupUtil.groupListByQuantity(allList, 50);
        int i = 0;
        List<String> list = null;
        for (int c = 0; c < groupList.size(); c++) {
            list = groupList.get(c);
            
            System.out.println("第" + (c + 1) + "组: ");
            for (String temp : list) {
                System.out.print(temp + ", ");
            }
            System.out.println();
        }
    }
    
    /**
     * 集合只有一个记录的情况
     */
    @Test
    public void test3() {
        List<String> allList = new ArrayList<String>();
        for (int i = 1; i <= 1; i++) {
            allList.add(i  + "");
        }
        
        List<List<String>> groupList = CollectionGroupUtil.groupListByQuantity(allList, 50);
        int i = 0;
        List<String> list = null;
        for (int c = 0; c < groupList.size(); c++) {
            list = groupList.get(c);
            
            System.out.println("第" + (c + 1) + "组: ");
            for (String temp : list) {
                System.out.print(temp + ", ");
            }
            System.out.println();
        }
    }
    
    /**
     * 空集合的情况
     */
    @Test
    public void test4() {
        List<List<String>> groupList = CollectionGroupUtil.groupListByQuantity(null, 50);
        System.out.println(groupList);
        
        groupList = CollectionGroupUtil.groupListByQuantity(new ArrayList(), 50);
        System.out.println(groupList);
    }
    
    /**
     * 集合刚满一个分组的情况
     */
    @Test
    public void test5() {
        List<String> allList = new ArrayList<String>();
        for (int i = 1; i <= 50; i++) {
            allList.add(i  + "");
        }
        
        List<List<String>> groupList = CollectionGroupUtil.groupListByQuantity(allList, 50);
        int i = 0;
        List<String> list = null;
        for (int c = 0; c < groupList.size(); c++) {
            list = groupList.get(c);
            
            System.out.println("第" + (c + 1) + "组: ");
            for (String temp : list) {
                System.out.print(temp + ", ");
            }
            System.out.println();
        }
    }
    
}
View Code

 

【Java】List集合按数量分组

原文:http://www.cnblogs.com/nick-huang/p/5139771.html

(1)
(0)
   
举报
评论 一句话评论(0
关于我们 - 联系我们 - 留言反馈 - 联系我们:wmxa8@hotmail.com
© 2014 bubuko.com 版权所有
打开技术之扣,分享程序人生!