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uva 10929 - You can say 11

时间:2016-01-19 01:30:48      阅读:146      评论:0      收藏:0      [点我收藏+]

 

 1 #include <cstdio>
 2 using namespace std;
 3 
 4 char in[1100];
 5 
 6 int main()
 7 {
 8     while(gets(in))
 9     {
10         if(in[0] == 0 && in[1] == 0) break;
11 
12         int s = 0;
13         for (int i = 0; in[i] != 0; i++)
14         {
15             s += (in[i] - 0);
16             s *= 10;
17             s %= 11;
18         }
19         printf(s == 0 ? "%s is a multiple of 11.\n" : "%s is not a multiple of 11.\n", in);
20     }
21     return 0;
22 }

 第二种思路不错,多想想!

 1 #include<iostream>
 2 #include<string>
 3 
 4 using namespace std;
 5 
 6 int main(){
 7     //freopen("in.txt","r",stdin);
 8     //freopen("out.txt","w",stdout);
 9 
10     char num[1001];
11 
12     int sum;
13 
14     while(1){
15         cin>>num;
16 
17         if(num[0]==0 && strlen(num)==1) break;
18 
19         sum=0;
20 
21         for(int i=0;i<strlen(num);i+=2) sum+=num[i]-0;
22         for(int i=1;i<strlen(num);i+=2) sum-=num[i]-0;
23         cout << "sum: " << sum << endl;
24         if(sum%11==0) cout<<num<<" is a multiple of 11."<<endl;
25         else cout<<num<<" is not a multiple of 11."<<endl;
26     }
27 }

 

uva 10929 - You can say 11

原文:http://www.cnblogs.com/aze-003/p/5140938.html

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