题目:
Given an absolute path for a file (Unix-style), simplify it.
For example,
path = "/home/"
, => "/home"
path = "/a/./b/../../c/"
, => "/c"
"/../"
?"/"
.‘/‘
together, such as "/home//foo/"
."/home/foo"
.思路:
字符串处理,由于".."是返回上级目录(如果是根目录则不处理),因此可以考虑用栈记录路径名,以便于处理。需要注意几个细节:
最后,再逐个取出栈中元素(即已保存的路径名),用‘/‘分隔并连接起来,不过要注意顺序呦。
/** * @param {string} path * @return {string} */ var simplifyPath = function(path) { var stack=[],len=path.length,i=0; while(i<len){ //跳过开头的‘/‘‘ while(path[i]==‘/‘&&i<len){ i++; } var s=‘‘; while(i<len&&path[i]!=‘/‘){ s+=path[i++]; } //如果是".."则需要弹栈,否则入栈 if(".." == s && stack.length!=0){ stack.pop(); }else if(s != "" && s != "." && s != ".."){ stack.push(s); } } //如果栈为空,说明为根目录,只有斜线‘/‘ if(stack.length==0){ return ‘/‘ } var res=‘‘; while(stack.length!=0){ res = "/" + stack.pop() + res; } return res; };
原文:http://www.cnblogs.com/shytong/p/5186331.html