原题链接在这里:https://leetcode.com/problems/inorder-successor-in-bst/
Given a binary search tree and a node in it, find the in-order successor of that node in the BST.
Note: If the given node has no in-order successor in the tree, return null
.
利用BST性质,找successor时只用找一边。若是p.val < root.val 就把root 赋值给 successor, 否则root = root.right.
Time Complexity: O(h). Space: O(1).
AC Java:
1 /** 2 * Definition for a binary tree node. 3 * public class TreeNode { 4 * int val; 5 * TreeNode left; 6 * TreeNode right; 7 * TreeNode(int x) { val = x; } 8 * } 9 */ 10 public class Solution { 11 public TreeNode inorderSuccessor(TreeNode root, TreeNode p) { 12 if(root == null || p == null){ 13 return null; 14 } 15 TreeNode successor = null; 16 while(root != null){ 17 if(p.val < root.val){ 18 successor = root; 19 root = root.left; 20 }else{ 21 root = root.right; 22 } 23 } 24 return successor; 25 } 26 }
LeetCode Inorder Successor in BST
原文:http://www.cnblogs.com/Dylan-Java-NYC/p/5206006.html