首页 > 其他 > 详细

LeetCode Inorder Successor in BST

时间:2016-02-22 06:43:40      阅读:220      评论:0      收藏:0      [点我收藏+]

原题链接在这里:https://leetcode.com/problems/inorder-successor-in-bst/

Given a binary search tree and a node in it, find the in-order successor of that node in the BST.

Note: If the given node has no in-order successor in the tree, return null.

 

Show Company Tags
Show Tags
Show Similar Problems

利用BST性质,找successor时只用找一边。若是p.val < root.val 就把root 赋值给 successor, 否则root = root.right.

Time Complexity: O(h). Space: O(1).

AC Java:

 1 /**
 2  * Definition for a binary tree node.
 3  * public class TreeNode {
 4  *     int val;
 5  *     TreeNode left;
 6  *     TreeNode right;
 7  *     TreeNode(int x) { val = x; }
 8  * }
 9  */
10 public class Solution {
11     public TreeNode inorderSuccessor(TreeNode root, TreeNode p) {
12         if(root == null || p == null){
13             return null;
14         }
15         TreeNode successor = null;
16         while(root != null){
17             if(p.val < root.val){
18                 successor = root;
19                 root = root.left;
20             }else{
21                 root = root.right;
22             }
23         }
24         return successor;
25     }
26 }

 

LeetCode Inorder Successor in BST

原文:http://www.cnblogs.com/Dylan-Java-NYC/p/5206006.html

(0)
(0)
   
举报
评论 一句话评论(0
关于我们 - 联系我们 - 留言反馈 - 联系我们:wmxa8@hotmail.com
© 2014 bubuko.com 版权所有
打开技术之扣,分享程序人生!