首页 > 数据库技术 > 详细

SQL

时间:2016-03-07 11:59:21      阅读:262      评论:0      收藏:0      [点我收藏+]
SELECT 
    T.DID AS DID ,
    T.YEAR AS YEAR,
    T.MONTH AS MONTH,
    T.UP_TIME AS UP_TIME,
    T.IN_NAME AS IN_NAME,
    T.IN_CODE AS IN_CODE ,
    T.C_NAME AS C_NAME,
    T.C_CODE AS C_CODE ,
    T.ORG_NAME AS ORG_NAME ,
    T.ORG_CODE AS ORG_CODE,
    (case when X.COUNT is null then 0 else X.COUNT end) as COUNT
FROM ( SELECT A.DID AS DID ,
              A.YEAR AS YEAR,
              A.MONTH AS MONTH,
              A.UP_TIME AS UP_TIME,
              B.IN_NAME AS IN_NAME,
              B.IN_CODE AS IN_CODE ,
              B.C_NAME AS C_NAME,
              B.C_CODE AS C_CODE ,
              B.ORG_NAME AS ORG_NAME ,
              B.ORG_CODE AS ORG_CODE
       FROM
            (SELECT DID,YEAR,MONTH,UP_TIME,
                    FACT_NAME,
                    FACT_CODE
             FROM CDA_FI_EQ_BOOK_M_LIST M
             WHERE 1=1
             AND NOT EXISTS
             (SELECT DID
                  FROM EQ_BOOK_M_CHECK_LOG L
                  WHERE 1=1
                  AND M.DID = L.DID)) A
             LEFT JOIN ORG_ORDER B ON A.FACT_CODE = B.ORG_CODE
             WHERE 1=1 ) T left join
(SELECT DID,COUNT(1) AS COUNT FROM CDA_FID_EQ_BOOK_M_1 Q group by DID HAVING NOT EXISTS(SELECT DID FROM EQ_BOOK_M_CHECK_LOG P WHERE 1=1 AND Q.DID = P.DID)) X on T.DID = X.DID

  

SQL

原文:http://www.cnblogs.com/dbqjava/p/5249862.html

(0)
(0)
   
举报
评论 一句话评论(0
关于我们 - 联系我们 - 留言反馈 - 联系我们:wmxa8@hotmail.com
© 2014 bubuko.com 版权所有
打开技术之扣,分享程序人生!