lintcode-easy-Trailing Zeros

class Solution {
    /*
     * param n: As desciption
     * return: An integer, denote the number of trailing zeros in n!
     */
    public long trailingZeros(long n) {
        // write your code here
        if(n <= 0)  
            return 0;
        
        long result = 0;
        
        for(long i = 5; n / i > 0; i *= 5){
            result += n / i;
        }
        
        return result;
    }
};