lambda语句与匿名函数

>>> def fun1(x):
	return x * 2 + 1

>>> lambda x:x * 2 + 1
<function <lambda> at 0x000000F732724400>
>>> g = lambda x:x * 2 + 1
>>> g(5)
11

#lambda语法是 lambda [函数参数]:[函数返回值]

>>> add(1,2)
1 + 2 = 3

>>> lambda x,y:print(x,‘+‘,y,‘=‘,x+y)
<function <lambda> at 0x000000F73272D488>

>>> g = lambda x,y:print(x,‘+‘,y,‘=‘,x+y)
>>> g(2,3)
2 + 3 = 5