Given two integers n and k, return all possible combinations of k numbers out of 1 ... n.
For example,
If n = 4 and k = 2, a solution is:
[[2,4],[3,4],[2,3],[1,2],[1,3],[1,4]]
思路还是一样的,回溯算法,只是判断条件稍微不通而已
public class Solution { /** * @param n: Given the range of numbers * @param k: Given the numbers of combinations * @return: All the combinations of k numbers out of 1..n */ public List<List<Integer>> combine(int n, int k) { // write your code here List<List<Integer>> result = new ArrayList<List<Integer>>(); if(n < 1 || k > n) return result; List<Integer> line = new ArrayList<Integer>(); helper(result, line, n, k, 1); return result; } public void helper(List<List<Integer>> result, List<Integer> line, int n, int k, int start){ if(line.size() == k){ result.add(new ArrayList<Integer>(line)); return; } for(int i = start; i <= n; i++){ line.add(i); helper(result, line, n, k, i + 1); line.remove(line.size() - 1); } return; } }
原文:http://www.cnblogs.com/goblinengineer/p/5282037.html