三子棋游戏实现

   
#include<stdio.h>
#include<stdlib.h>
#include<time.h>

void chess_board(char arr[3][3])
{
   int i = 0;
   int j = 0;
   for (i = 0; i < 3; i++)
   {
       printf( " %c | %c | %c \n", arr [i][0], arr[i][1], arr[i][2]);
       if (i<2)
       printf( "---|---|---\n");
    }
}
int success_or_failure(char arr[3][3])
{
     int i = 0;
     int j = 0;
     for (i = 0; i < 3; i++)
     {
        if ((arr [i][0] == arr[i][1]) && ( arr[i][j] == arr [i][2]))
          {
              if (arr [i][0] == ‘#‘)
                 return 1;
              else if (arr[i][0] == ‘0‘)
                  return -1;
            }
      }
      for (j = 0; j < 3; j++)
       {
               if ((arr [0][j] == arr[1][j]) && ( arr[1][j] == arr [2][j]))
                 {
                       if (arr [0][j] == ‘#‘)
                           return 1;
                       else if (arr[0][j] == ‘0‘)
                            return -1;
                  }
        }
        if ((arr [0][0] == arr[1][1]) && ( arr[0][0] == arr [2][2]))
          {
              if (arr [1][1] == ‘#‘)
                  return 1;
               else if (arr[1][1] == ‘0‘)
                  return -1;
          }
        if ((arr [0][2] == arr[1][1]) && ( arr[0][2] == arr [2][0]))
          {
               if (arr [1][1] == ‘#‘)
                   return 1;
               else if (arr[1][1] == ‘0‘)
                   return -1;
          }
        for (i = 0; i < 3; i++)
         {
               for (j = 0; j < 3; j++)
                 {
                     if (arr [i][j] == ‘ ‘)
                          return 0;
                 }
         }
         return -2;
}
int user_game(char arr[3][3])
{
      int x = 0;
       int y = 0;
       while (1)
       {
         printf( "please user input:(x, y) " );
          scanf( "%d%d", &x, &y);
          printf( "\n");
          if ((x<1 && x>3) || (y<1 && y>3))
          {
            printf( "地址无效，请重新输入\n" );                          break;
             }
         if (arr [x - 1][y - 1] == ‘ ‘)
          {                                                      arr[x - 1][y - 1] = ‘#‘ ;
              break;
          }
           printf( "地址无效，请重新输入\n" );
      }
      chess_board( arr);
      int ret=success_or_failure(arr );
      return ret;
}
int computer_game(char arr[3][3])
{
         printf( "computer input:\n\n");
         int x = 0;
         int y = 0;
         while (1)
      {
         srand(( unsigned)time(NULL ));
         x = rand() % 3;
         srand(( unsigned)time(NULL ));
         y = rand() % 3;
         if (arr [x][y] == ‘ ‘)                                 break;
      }
      arr[x][y]= ‘0‘ ;
      chess_board( arr);
      int ret=success_or_failure(arr );
      return ret;
}
int main()
{
        printf( "***************************\n" );
     printf( "*******        *******\n");
     printf( "*******1.go   0.exit*******\n");
     printf( "*******        *******\n");
     printf( "******************************\n");
        printf( "***************************\n\n\n");
     char arr[3][3];
     while (1)
     {
       for (int i = 0; i < 3; i++)
        {
          for (int j = 0; j<3; j++)
            {
               arr[i][j] = ‘ ‘;
            }
        }
       int count = 0;
         printf( "\nplease choice:1 or 0 : " );
       scanf( "%d", &count);
       if (count == 0)
         {
         exit( EXIT_FAILURE);
       }
      else if (count == 1)
       {
          printf( "\n****游戏开始****\n\n" );
          while (1)
          {                                                 int n1 = user_game(arr);
             {
                                                            if (n1 == 1)
                                                             {
                    printf( "****恭喜玩家赢了****\n" );
                    break;
                                                             }
                                                             }                                       int n2 = computer_game(arr);
                                                     {
                                                        if (n2 == -1)
                                                        {
               printf( "****电脑赢了****\n" );
                break;
            }
         }
                                                     if ((n1 == -2) || (n2 == -2))
                                                       {
            printf( "*****平局******\n" );
            break;
         }
                                                      }
        }
  printf( "\n再来一局\n\n" );
   }
 return 0;
}

本文出自 “11132019” 博客，请务必保留此出处http://11142019.blog.51cto.com/11132019/1757266

三子棋游戏实现

原文：http://11142019.blog.51cto.com/11132019/1757266