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SPOJ - 1112. Number Steps 题解

时间:2014-04-23 02:15:50      阅读:537      评论:0      收藏:0      [点我收藏+]

Starting from point (0,0) on a plane, we have written all non-negative integers 0, 1, 2,... as shown in the figure. For example, 1, 2, and 3 has been written at points (1,1), (2,0), and (3, 1) respectively and this pattern has continued.

 

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You are to write a program that reads the coordinates of a point (x, y), and writes the number (if any) that has been written at that point. (x, y) coordinates in the input are in the range 0...10000.

 

Input

The first line of the input is N, the number of test cases for this problem. In each of the N following lines, there is x, and y representing the coordinates (x, y) of a point.

 

Output

For each point in the input, write the number written at that point or write No Number if there is none.

 

Example

Input:
3
4 2
6 6
3 4

Output:
6
12
No Number

本程序优雅的地方就是充分考虑好各种情况,然后合并起来,代码就简洁了

#include <iostream>
#include <vector>
#include <string>
using namespace std;

void NumberSteps()
{
	int T = 0;
	cin>>T;
	int x = 0, y = 0;
	while (T--)
	{
		cin>>x>>y;
		if (x != y && y+2 != x) cout<<"No Number"<<endl;
		else
		{
			if (x % 2) cout<<x+y-1<<endl;
			else cout<<x+y<<endl;
		}
	}
}

int main()
{
	NumberSteps();	
	return 0;
}




SPOJ - 1112. Number Steps 题解,布布扣,bubuko.com

SPOJ - 1112. Number Steps 题解

原文:http://blog.csdn.net/kenden23/article/details/24328225

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