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LeetCode Invert Binary Tree

时间:2016-03-29 12:14:58      阅读:214      评论:0      收藏:0      [点我收藏+]

Invert a binary tree.

     4
   /     2     7
 / \   / 1   3 6   9

to

     4
   /     7     2
 / \   / 9   6 3   1

Trivia:
This problem was inspired by this original tweet by Max Howell:

Google: 90% of our engineers use the software you wrote (Homebrew), but you can’t invert a binary tree on a whiteboard so fuck off.

这个题目只要实现一个递归调用即可

/**
 * Definition for a binary tree node.
 * struct TreeNode {
 *     int val;
 *     TreeNode *left;
 *     TreeNode *right;
 *     TreeNode(int x) : val(x), left(NULL), right(NULL) {}
 * };
 */
class Solution {
public:
    TreeNode* invertTree(TreeNode* root) {
        TreeNode *temp;
        if (!root||((!root->left)&&(!root->right)))return root;
        else
        {
            temp=invertTree(root->right);
            root->right=invertTree(root->left);
            root->left = temp;
        }
        return root;
    }
};

 

LeetCode Invert Binary Tree

原文:http://www.cnblogs.com/csudanli/p/5332134.html

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