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基础题 密码学的力量 数学

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http://uva.onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&page=show_problem&problem=49

 Power of Cryptography 

 

Background

Current work in cryptography involves (among other things) large prime numbers and computing powers of numbers modulo functions of these primes. Work in this area has resulted in the practical use of results from number theory and other branches of mathematics once considered to be of only theoretical interest.

This problem involves the efficient computation of integer roots of numbers.

 

The Problem

Given an integer bubuko.com,布布扣 and an integer bubuko.com,布布扣 you are to write a program that determines bubuko.com,布布扣 , the positive bubuko.com,布布扣 root of p. In this problem, given such integers n and pp will always be of the form bubuko.com,布布扣 for an integer k (this integer is what your program must find).

 

The Input

The input consists of a sequence of integer pairs n and p with each integer on a line by itself. For all such pairs bubuko.com,布布扣 ,bubuko.com,布布扣 and there exists an integer kbubuko.com,布布扣 such that bubuko.com,布布扣 .

 

The Output

For each integer pair n and p the value bubuko.com,布布扣 should be printed, i.e., the number k such that bubuko.com,布布扣 .

 

Sample Input

 

2
16
3
27
7
4357186184021382204544

 

Sample Output

 

4
3
1234

bubuko.com,布布扣
 1 /*************************************************************************
 2     > File Name: 1234.cpp
 3     > Author: acmicpcstar
 4     > Mail: acmicpcstar@gmail.com
 5     > Created Time: 2014年04月23日 星期三 19时36分47秒
 6  ************************************************************************/
 7 
 8 #include<iostream>
 9 #include<cstring>
10 #include<cstdio>
11 #include<cmath>
12 using namespace std;
13 int main()
14 {double n,p;
15 while(cin>>n>>p)
16 printf("%.0lf\n",pow(p,1.0/n));
17 return 0;
18 }
bubuko.com,布布扣

本来想高精度的看了大牛的代码。。。直接惊奇~!

基础题 密码学的力量 数学,布布扣,bubuko.com

基础题 密码学的力量 数学

原文:http://www.cnblogs.com/acmicpcstar/p/3683800.html

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