(链表)2. Add Two Numbers

/**
 * Definition for singly-linked list.
 * public class ListNode {
 *     int val;
 *     ListNode next;
 *     ListNode(int x) { val = x; }
 * }
 */
public class Solution {
    public ListNode addTwoNumbers(ListNode l1, ListNode l2) {
     if (l1 == null)
			return l2;
		if (l2 == null)                  //这题看起来简单，但是花了很长时间啊，链表要遍历几次，但是这样写代码最短？实在不想再写了
			return l1;
		int temp = 0;
		ListNode p = l1;
		ListNode q = l2;
		ListNode longList = l1;
		ListNode la = l1;
		while (p != null && q != null) {
			p = p.next;
			q = q.next;
		}
		if (q == null) {
			q = l1;
			p = l2;
			longList = l1;
		} else {
			q = l2;
			p = l1;
			longList = l2;
		}
		while (p != null && q != null) {
			if (p.val + q.val + temp >= 10) {
				q.val = p.val + q.val + temp - 10;
				temp = 1;
			} else {
				q.val = q.val + p.val + temp;
				temp = 0;
			}
			p = p.next;
			q = q.next;
		}
		while (q != null) {
			if (q.val + temp >= 10) {
				q.val = q.val + temp - 10;
				temp = 1;
			} else {
				q.val = q.val + temp;
				temp = 0;
			}
			q = q.next;
		}
		if (temp == 1) {
			ListNode last = new ListNode(1);
			last.next = null;
			p = longList;
			while (p.next!= null)
				p = p.next;
			la = p;
			la.next = last;
		}

		return longList;
    }
}