Java 中 手动抛出异常: throw new Exception("错误信息") 错误信息的获得

 1 int dylist = dyDao.findByHql("from ZcZcsqdy where yxbz = 1 and zcsqId = "+sqId, null).size();
 2                     if(dylist <= 0){
 3 //                        logger.error("未添加任何资产//////////");
 4 //                        return 0;
 5                         throw new Exception("未添加资产,请重新添加");
 6                     }
 7 
 8 
 9 
10 
11 
12 //捕获异常
13 
14 
15 try{
16             processService.doNextFlow(getRequest());
17         }catch(Exception ex){
18             logger.error("error:" + ex.getMessage());
19             ex.printStackTrace();
20             setJsonString("{success:false,info:\""+ ex.getCause().getMessage()+"\"}");
21         }