思路:枚举每个点,看看它是否同时小于/大于前一个点和后一个点
1 import java.util.Scanner; 2 public class Main { 3 public static void main(String[] args) { 4 Scanner cin = new Scanner(System.in); 5 int n = cin.nextInt(); 6 int[] arr = new int[n]; 7 for (int i = 0; i < n; i++) 8 arr[i] = cin.nextInt(); 9 int ans = 0; 10 for (int i = 1; i < n - 1; i++) 11 if (arr[i] < arr[i - 1] && arr[i] < arr[i + 1] || arr[i] > arr[i - 1] && arr[i] > arr[i + 1]) 12 ans++; 13 System.out.println(ans); 14 } 15 }
原文:http://www.cnblogs.com/iRedBean/p/5385035.html