3 4 1 1 1 1 5 10 20 30 40 50 8 1 7 2 6 4 4 3 5
yes no yes
#include <stdio.h>
#include <string.h>
#include <iostream>
#include <algorithm>
#define maxn 22
int L[maxn], n, tar, times;
bool vis[maxn], ok;
bool DFS(int k, int leftLen) {
if(!leftLen) {
if(++times == 4) return true;
for(int i = 1; i < n; ++i) {
if(!vis[i]) {
vis[i] = 1;
if(DFS(i + 1, tar - L[i]))
return true;
else {
--times;
vis[i] = 0;
return false;
}
}
}
}
int i;
for(i = k; i < n; ++i) {
if(!vis[i] && L[i] <= leftLen) {
vis[i] = 1;
if(L[i-1] == L[i] && !vis[i-1]) {
vis[i] = 0;
continue;
}
if(DFS(i+1, leftLen - L[i]))
return true;
vis[i] = 0;
}
}
return false;
}
int main() {
int t, i;
scanf("%d", &t);
while(t--) {
scanf("%d", &n);
tar = 0;
for(i = 0; i < n; ++i) {
scanf("%d", &L[i]);
vis[i] = 0; tar += L[i];
}
if(tar % 4) {
printf("no\n");
continue;
}
tar /= 4;
std::sort(L, L + n, std::greater<int>());
if(L[0] > tar) {
printf("no\n");
continue;
}
times = 0; vis[0] = 1;
DFS(1, tar - L[0]);
printf(times == 4 ? "yes\n" : "no\n");
}
return 0;
}原文:http://www.cnblogs.com/bhlsheji/p/5386613.html