Time Limit: 2 second(s) | Memory Limit: 32 MB |
Alice and Bob are playing a stone game. Initially there are n piles of stones and each pile contains some stone. Alice stars the game and they alternate moves. In each move, a player has to select any pile and should remove at least one and no more than half stones from that pile. So, for example if a pile contains 10 stones, then a player can take at least 1 and at most 5 stones from that pile. If a pile contains 7 stones; at most 3 stones from that pile can be removed.
Both Alice and Bob play perfectly. The player who cannot make a valid move loses. Now you are given the information of the piles and the number of stones in all the piles, you have to find the player who will win if both play optimally.
Input starts with an integer T (≤ 100), denoting the number of test cases.
Each case starts with a line containing an integer n (1 ≤ n ≤ 1000). The next line contains n space separated integers ranging in [1, 109]. The ith integer in this line denotes the number of stones in the ith pile.
For each case, print the case number and the name of the player who will win the game.
Sample Input |
Output for Sample Input |
5 1 1 3 10 11 12 5 1 2 3 4 5 2 4 9 3 1 3 9 |
Case 1: Bob Case 2: Alice Case 3: Alice Case 4: Bob Case 5: Alice |
题目大意:
#include <iostream> #include <cstdio> #include <cstring> using namespace std; const int MAXN = 1e3+5; int sg[MAXN]; int hash[MAXN]; void get_sg() { memset(sg, 0, sizeof(sg)); for(int i=1; i<MAXN; i++) { memset(hash, 0, sizeof(hash)); for(int j=1; j<=i/2; j++) { hash[sg[i-j]] = 1; } int j; for(j=0; ;j++) { if(!hash[j]) break; } sg[i] = j; } for(int i=1; i<=30; i++) cout<<sg[i]<<" "; } int main() { ///get_sg(); int T; scanf("%d",&T); for(int cas=1; cas<=T; cas++) { int m, x, ans=0; scanf("%d",&m); for(int i=0; i<m; i++) { scanf("%d",&x); while(x&1) x>>=1; ans ^= (x>>1); } if(!ans) printf("Case %d: Bob\n",cas); else printf("Case %d: Alice\n",cas); } return 0; }
Light OJ 1296 - Again Stone Game
原文:http://blog.csdn.net/qingshui23/article/details/51169067