首页 > 其他 > 详细

136. Single Number

时间:2016-04-19 13:56:31      阅读:218      评论:0      收藏:0      [点我收藏+]

Given an array of integers, every element appears twice except for one. Find that single one.

Note:
Your algorithm should have a linear runtime complexity. Could you implement it without using extra memory?

 

Similar: 

137. Single Number II

260. Single Number III

268. Missing Number

287. Find the Duplicate Number

1 public class Solution {
2     public int singleNumber(int[] nums) {
3         int ret = nums[0];
4         for (int i = 1; i < nums.length; i++) {
5             ret ^= nums[i];
6         }
7         return ret;
8     }
9 }

 

136. Single Number

原文:http://www.cnblogs.com/joycelee/p/5407706.html

(0)
(0)
   
举报
评论 一句话评论(0
关于我们 - 联系我们 - 留言反馈 - 联系我们:wmxa8@hotmail.com
© 2014 bubuko.com 版权所有
打开技术之扣,分享程序人生!