2014-04-28 22:05
题目:写个程序判断三连棋哪一方赢了。
解法:三个相同的棋子连成一条横线,竖线或者对角线就判断为赢了。
代码:
1 // 17.2 Write an algorithm to check if someone has won the tic-tac-toe game. 2 // Here is the game: 3 // xo- 4 // ox- 5 // --x 6 // ‘x‘ won the game. 7 // Rule: anyone who gets three consecutive pieces in a row, a column or a diagonal line first wins. 8 #include <cstdio> 9 using namespace std; 10 11 int check(int a[][3]) 12 { 13 if (a == nullptr) { 14 return -1; 15 } 16 17 int i; 18 for (i = 0; i < 3; ++i) { 19 if (a[i][0] == a[i][1] && a[i][1] == a[i][2] && a[i][2] != 0) { 20 return a[i][2]; 21 } 22 if (a[0][i] == a[1][i] && a[1][i] == a[2][i] && a[2][i] != 0) { 23 return a[i][2]; 24 } 25 } 26 if (a[0][0] == a[1][1] && a[1][1] == a[2][2] && a[2][2] != 0) { 27 return a[2][2]; 28 } 29 if (a[0][2] == a[1][1] && a[1][1] == a[2][0] && a[2][0] != 0) { 30 return a[2][2]; 31 } 32 33 return 0; 34 } 35 36 int main() 37 { 38 int a[3][3]; 39 int i, j; 40 41 for (i = 0; i < 3; ++i) { 42 for (j = 0; j < 3; ++j) { 43 scanf("%d", &a[i][j]); 44 } 45 } 46 printf("%d\n", check(a)); 47 48 return 0; 49 }
《Cracking the Coding Interview》——第17章:普通题——题目2,布布扣,bubuko.com
《Cracking the Coding Interview》——第17章:普通题——题目2
原文:http://www.cnblogs.com/zhuli19901106/p/3698070.html