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LeetCode OJ 236. Lowest Common Ancestor of a Binary Tree

时间:2016-05-10 18:35:43      阅读:201      评论:0      收藏:0      [点我收藏+]

Given a binary tree, find the lowest common ancestor (LCA) of two given nodes in the tree.

According to the definition of LCA on Wikipedia: “The lowest common ancestor is defined between two nodes v and w as the lowest node in T that has both v and w as descendants (where we allow a node to be a descendant of itself).”

        _______3______
       /                  ___5__          ___1__
   /      \        /         6      _2       0       8
         /           7   4

For example, the lowest common ancestor (LCA) of nodes 5 and 1 is 3. Another example is LCA of nodes 5 and 4 is 5, since a node can be a descendant of itself according to the LCA definition.

这个题目一开始很是困惑~不知道该如何下手。发现别人的解答很是简单,发现递归真是一门学问啊!

 1 /**
 2  * Definition for a binary tree node.
 3  * public class TreeNode {
 4  *     int val;
 5  *     TreeNode left;
 6  *     TreeNode right;
 7  *     TreeNode(int x) { val = x; }
 8  * }
 9  */
10 public class Solution {
11     public TreeNode lowestCommonAncestor(TreeNode root, TreeNode p, TreeNode q) {
12         if(root == null) return null;
13         if(root == p || root == q) return root;
14         TreeNode left = lowestCommonAncestor(root.left, p, q);
15         TreeNode right = lowestCommonAncestor(root.right, p, q);
16         return left != null && right != null ? root : left == null ? right : left; 
17     }
18     
19 }

 

LeetCode OJ 236. Lowest Common Ancestor of a Binary Tree

原文:http://www.cnblogs.com/liujinhong/p/5478740.html

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