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[LeetCode101]Symmetric Tree

时间:2016-05-14 18:44:53      阅读:284      评论:0      收藏:0      [点我收藏+]

题目:

Given a binary tree, check whether it is a mirror of itself (ie, symmetric around its center).

For example, this binary tree is symmetric:

    1
   /   2   2
 / \ / 3  4 4  3

 

But the following is not:

    1
   /   2   2
   \      3    3

 

Note:
Bonus points if you could solve it both recursively and iteratively.

分类:Tree BFS DFS

代码:

 1 /**
 2  * Definition for a binary tree node.
 3  * struct TreeNode {
 4  *     int val;
 5  *     TreeNode *left;
 6  *     TreeNode *right;
 7  *     TreeNode(int x) : val(x), left(NULL), right(NULL) {}
 8  * };
 9  */
10 class Solution {
11 public:
12     
13     bool isSymmetric(TreeNode *root) {
14         if (!root) return true;
15         return helper(root->left, root->right);
16     }
17 
18     bool helper(TreeNode* p, TreeNode* q) {
19         if (!p && !q) {
20             return true;
21         } else if (!p || !q) {
22             return false;
23         }
24 
25         if (p->val != q->val) {
26             return false;
27         }
28 
29         return helper(p->left,q->right) && helper(p->right, q->left); 
30     }
31 };

 

[LeetCode101]Symmetric Tree

原文:http://www.cnblogs.com/zhangbaochong/p/5492988.html

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