Write a function to delete a node (except the tail) in a singly linked list, given only access to that node.
Supposed the linked list is 1 -> 2 -> 3 -> 4 and you are given the third node with value 3, the linked list should become 1 -> 2 -> 4 after calling your function.
1 /** 2 * Definition for singly-linked list. 3 * struct ListNode { 4 * int val; 5 * struct ListNode *next; 6 * }; 7 */ 8 void deleteNode(struct ListNode* node) { 9 if(node == NULL || node->next == NULL) 10 return; 11 node->val = node->next->val; //把下一节点值赋予删除当前节点 12 node->next = node->next->next; //删除下一个节点 13 }
237. Delete Node in a Linked List
原文：http://www.cnblogs.com/boluo007/p/5505813.html