Given a string s consists of upper/lower-case alphabets and empty space characters ‘
‘, return the length of last word in the string.
If the last word does not exist, return 0.
Note: A word is defined as a character sequence consists of non-space characters only.
For example,
Given s = "Hello World",
return 5.
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c++ code:
class Solution {
public:
int lengthOfLastWord(string s) {
int tail = s.size() - 1;
int cnt=0;
while(tail>=0 && ' ' == s[tail]) tail--;
while(tail>=0 && s[tail]!=' ') {
cnt++;
tail--;
}
return cnt;
}
};原文：http://blog.csdn.net/itismelzp/article/details/51473821