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LeetCode:Word Break

时间:2016-06-12 02:42:25      阅读:125      评论:0      收藏:0      [点我收藏+]

Word Break


Total Accepted: 89221 Total Submissions: 347438 Difficulty: Medium

Given a string s and a dictionary of words dict, determine if s can be segmented into a space-separated sequence of one or more dictionary words.

For example, given
s = "leetcode",
dict = ["leet", "code"].

Return true because "leetcode" can be segmented as "leet code".

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java code:

public class Solution {
    public boolean wordBreak(String s, Set<String> wordDict) {
        
        boolean[] dp = new boolean[s.length() + 1];
        dp[0] = true;
        
        for(int i=1;i<=s.length();i++) {
            for(int j=0;j<i;j++) {
                if(dp[j] && wordDict.contains(s.substring(j,i))) {
                    dp[i] = true;
                    break;
                }
            }
        }
        return dp[s.length()];
    }
}


LeetCode:Word Break

原文:http://blog.csdn.net/itismelzp/article/details/51615767

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