Java判断两个时间差值

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DateFormat df = new SimpleDateFormat("yyyy-MM-dd HH:mm:ss");
try{

  Date d1 = df.parse("2016-06-06 10:07:40");
 
  Date d2 = df.parse("2015-06-05 11:30:24");
  long diff = d1.getTime() - d2.getTime();//这样得到的差值是微秒级别

  long days = diff / (1000 * 60 * 60 * 24);

  long hours = (diff-days*(1000 * 60 * 60 * 24))/(1000* 60 * 60);

  long minutes = (diff-days*(1000 * 60 * 60 * 24)-hours*(1000* 60 * 60))/(1000* 60);

  System.out.println(""+days+"天"+hours+"小时"+minutes+"分");

}
catch (Exception e)
{
}

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Java判断两个时间差值

原文：http://hazeover.iteye.com/blog/2303257