The gray code is a binary numeral system where two successive values differ in only one bit.
Given a non-negative integer n representing the total number of bits in the code, print the sequence of gray code. A gray code sequence must begin with 0.
For example, given n = 2, return [0,1,3,2]
. Its gray code sequence is:
00 - 0 01 - 1 11 - 3 10 - 2
Note:
For a given n, a gray code sequence is not uniquely defined.
For example, [0,2,3,1]
is also a valid gray code sequence according to the above definition.
For now, the judge is able to judge based on one instance of gray code sequence. Sorry about that.
1 public class Solution { 2 public List<Integer> grayCode(int n) { 3 List<Integer> ans = new ArrayList<Integer>(); 4 int len = (int)Math.pow(2,n); 5 for(int i = 0; i< len ;i++){ 6 ans.add(i^(i>>1));// 按照数学公式的解法。G(N) = (B(n)/2) XOR B(n). 7 } 8 return ans; 9 } 10 }
二进制数转格雷码
(假设以二进制为0的值做为格雷码的0)
G:格雷码 B:二进制码
G(N) = (B(n)/2) XOR B(n).
以三位为例:
000^000-->000
001^000-->001
010^001-->011
011^001-->010
100^010-->110
101^010-->111
110^011-->101
111^011-->100
解法二: 可用递归。以后在总结。
参考帖子:
http://blog.csdn.net/makuiyu/article/details/44926463
http://www.cnblogs.com/peihao/p/5269151.html (第二个帖子描述的还是不够清晰一些)
原文:http://www.cnblogs.com/guoguolan/p/5619709.html