首页 > 其他 > 详细

HDU 2212 DFS

时间:2016-07-04 23:24:33      阅读:322      评论:0      收藏:0      [点我收藏+]

Problem Description

A DFS(digital factorial sum) number is found by summing the factorial of every digit of a positive integer.

For example ,consider the positive integer 145 = 1!+4!+5!, so it‘s a DFS number.

Now you should find out all the DFS numbers in the range of int( [1, 2147483647] ).

There is no input for this problem. Output all the DFS numbers in increasing order. The first 2 lines of the output are shown below.

Input

no input

Output

Output all the DFS number in increasing order.

Sample Output

1
2
......

Author

zjt

1 #include<stdio.h>
2 int main()
3 {
4     printf("1\n2\n145\n40585\n");
5     return 0;
6 }

 

 
 
敲代码算出来(时间有点长....发现只有四个答案就)
 

HDU 2212 DFS

原文:http://www.cnblogs.com/Annetree/p/5641841.html

(0)
(0)
   
举报
评论 一句话评论(0
关于我们 - 联系我们 - 留言反馈 - 联系我们:wmxa8@hotmail.com
© 2014 bubuko.com 版权所有
打开技术之扣,分享程序人生!