题目大意:
求区间最大子区间的和。
思路分析:
记录左最大,右最大,区间最大。
注意Q_L 和 Q_R 就好。
#include <cstdio> #include <iostream> #include <algorithm> #include <cstring> #define lson num<<1,s,mid #define rson num<<1|1,mid+1,e #define maxn 55555 using namespace std; int lef[maxn<<2]; int rig[maxn<<2]; int tre[maxn<<2]; int sum[maxn<<2]; void pushup(int num) { sum[num]=sum[num<<1]+sum[num<<1|1]; lef[num]=max(lef[num<<1],sum[num<<1]+lef[num<<1|1]); rig[num]=max(rig[num<<1|1],sum[num<<1|1]+rig[num<<1]); tre[num]=max(max(tre[num<<1],tre[num<<1|1]),rig[num<<1]+lef[num<<1|1]); } void build(int num,int s,int e) { if(s==e) { scanf("%d",&tre[num]); sum[num]=rig[num]=lef[num]=tre[num]; return ; } int mid=(s+e)>>1; build(lson); build(rson); pushup(num); } int Q_L(int num,int s,int e,int l,int r) { if(l<=s && r>=e) { return lef[num]; } int mid=(s+e)>>1; if(r<=mid)return Q_L(lson,l,r); else if(l>mid)return Q_L(rson,l,r); else { return max(lef[num<<1],max(sum[num<<1],sum[num<<1]+Q_L(rson,mid+1,r))); } } int Q_R(int num,int s,int e,int l,int r) { if(l<=s && r>=e) { return rig[num]; } int mid=(s+e)>>1; if(r<=mid)return Q_R(lson,l,r); else if(l>mid)return Q_R(rson,l,r); else { return max(rig[num<<1|1],max(sum[num<<1|1],sum[num<<1|1]+Q_R(lson,l,mid))); } } int query(int num,int s,int e,int l,int r) { if(l<=s && r>=e) { return tre[num]; } int mid=(s+e)>>1; if(r<=mid)return query(lson,l,r); else if(l>mid)return query(rson,l,r); else { return max(Q_R(lson,l,mid)+Q_L(rson,mid+1,r),max(query(lson,l,mid),query(rson,mid+1,r))); } } void update(int num,int s,int e,int pos,int val) { if(s==e) { sum[num]=tre[num]=lef[num]=rig[num]=val; return; } int mid=(s+e)>>1; if(pos<=mid)update(lson,pos,val); else update(rson,pos,val); pushup(num); } int main() { int n; while(scanf("%d",&n)!=EOF) { build(1,1,n); int m; scanf("%d",&m); while(m--) { int op,l,r; scanf("%d%d%d",&op,&l,&r); if(op) printf("%d\n",query(1,1,n,l,r)); else update(1,1,n,l,r); } } return 0; }
SPOJ GSS3 Can you answer these queries III (线段树),布布扣,bubuko.com
SPOJ GSS3 Can you answer these queries III (线段树)
原文:http://blog.csdn.net/u010709592/article/details/25166715