H-Index II -- LeetCode

Given an array of citations (each citation is a non-negative integer) of a researcher, write a function to compute the researcher‘s h-index.

According to the definition of h-index on Wikipedia: "A scientist has index h if h of his/her N papers have at least h citations each, and the other N − h papers have no more than h citations each."

For example, given citations = [3, 0, 6, 1, 5], which means the researcher has 5 papers in total and each of them had received 3, 0, 6, 1, 5 citations respectively. Since the researcher has 3 papers with at least 3 citations each and the remaining two with no more than 3 citations each, his h-index is 3.

Note: If there are several possible values for h, the maximum one is taken as the h-index.

 1 class Solution {
 2 public:
 3     int hIndex(vector<int>& citations) {
 4         int left = 0, right = citations.size() - 1;
 5         while (left <= right) {
 6             int mid = left + (right - left) / 2;
 7             if (citations[mid] < citations.size() - mid)
 8                 left = mid + 1;
 9             else if (mid > left && citations[mid - 1] >= citations.size() - (mid - 1))
10                 right = mid - 1;
11             else return citations.size() - mid;
12         }
13         return 0;
14     }
15 };

H-Index II -- LeetCode

原文：http://www.cnblogs.com/fenshen371/p/5769420.html