Flip Game -- LeetCode

You are playing the following Flip Game with your friend: Given a string that contains only these two characters: + and -, you and your friend take turns to flip two consecutive "++" into "--". The game ends when a person can no longer make a move and therefore the other person will be the winner.

Write a function to compute all possible states of the string after one valid move.

For example, given s = "++++", after one move, it may become one of the following states:

[
  "--++",
  "+--+",
  "++--"
]

If there is no valid move, return an empty list [].

 1 class Solution {
 2 public:
 3     vector<string> generatePossibleNextMoves(string s) {
 4         vector<string> res;
 5         for (int i = 0, n = s.size() - 1; i < n; i++)
 6             if (s[i] == ‘+‘ && s[i + 1] == ‘+‘) {
 7                 string temp = s;
 8                 temp[i] = temp[i + 1] = ‘-‘;
 9                 res.push_back(temp);
10             }
11         return res;
12     }
13 };

Flip Game -- LeetCode

原文：http://www.cnblogs.com/fenshen371/p/5769939.html