Time Limit: 16000/8000 MS (Java/Others) Memory Limit: 65536/65536 K (Java/Others)
Total Submission(s): 920 Accepted Submission(s): 388
/*
hdu 5002 (动态树lct)
problem:
给你一棵树树,主要包含四个操作:
1 x y u v:断开x,y之间的边 连接上u,v
2 x y w:将x->y之间的点权全部置为w
3 x y w:将x->y之间的点权全部加上w
4 x y:查询x->y之间第二大的
solve:
只是需要维护下第二大值,其它直接套模板
hhh-2016-08-20 17:21:29
*/
#pragma comment(linker,"/STACK:124000000,124000000")
#include <algorithm>
#include <iostream>
#include <cstdlib>
#include <cstdio>
#include <cstring>
#include <vector>
#include <map>
#define lson ch[0]
#define rson ch[1]
#define ll long long
#define clr(a,b) memset(a,b,sizeof(a))
#define key_val ch[ch[root][1]][0]
using namespace std;
const int maxn = 300100;
const int INF = 0x3f3f3f3f;
struct Node* null;
struct Node
{
Node* ch[2] ;
Node* fa;
int Size ;
int mMax ;
int sMax ;
int max_num ;
int Max_num ;
int val ;
int add ;
int same ;
int rev;
void newnode(int v)
{
val = v ;
mMax = v ;
sMax = -INF ;
Max_num = 1 ;
max_num = 0 ;
Size = 1 ;
add = 0 ;
same = -INF ;
fa = ch[0] = ch[1] = null ;
rev = 0;
}
void update_rev()
{
if(this == null)
return ;
swap(ch[0],ch[1]);
rev ^= 1;
}
void update_add(int v)
{
if(this == null )return ;
add += v;
mMax += v,val += v;
if(sMax != -INF) sMax += v;
}
void update_same(int v)
{
if(this == null) return ;
same = v;
add = 0,val = v,mMax = v;
sMax = -INF,Max_num = Size,max_num = 0;
}
void cal(int val,int num)
{
if ( val == -INF ) return ;
if ( val < sMax ) return ;
if ( val > mMax )
{
sMax = mMax ;
max_num = Max_num ;
mMax = val ;
Max_num = num ;
}
else if ( val == mMax )
{
Max_num += num ;
}
else if ( val > sMax )
{
sMax = val ;
max_num = num ;
}
else max_num += num ;
}
void push_up () {
Size = ch[0]->Size + 1 + ch[1]->Size ;
mMax = sMax = -INF ;
max_num = Max_num = 0 ;
cal ( val , 1 ) ;
cal ( ch[0]->mMax , ch[0]->Max_num ) ;
cal ( ch[0]->sMax , ch[0]->max_num ) ;
cal ( ch[1]->mMax , ch[1]->Max_num ) ;
cal ( ch[1]->sMax , ch[1]->max_num ) ;
}
void push_down()
{
if(rev)
{
ch[0]->update_rev();
ch[1]->update_rev();
rev = 0;
}
if(same != -INF)
{
ch[0]->update_same(same);
ch[1]->update_same(same);
same = -INF;
}
if(add)
{
ch[0]->update_add(add);
ch[1]->update_add(add);
add = 0;
}
}
void link_child ( Node* to , int d )
{
ch[d] = to;
to->fa = this ;
}
int isroot()
{
return fa == null || this != fa->ch[0] && this != fa->ch[1] ;
}
void down()
{
if ( !isroot () ) fa->down () ;
push_down () ;
}
void Rotate ( int d )
{
Node* f = fa ;
Node* ff = fa->fa ;
f->link_child ( ch[d] , !d ) ;
if ( !f->isroot () )
{
if ( ff->ch[0] == f ) ff->link_child ( this , 0 ) ;
else ff->link_child ( this , 1 ) ;
}
else fa = ff ;
link_child (f,d) ;
f->push_up () ;
}
void splay ()
{
down () ;
while ( !isroot () ) {
if ( fa->isroot () ) {
this == fa->ch[0] ? Rotate ( 1 ) : Rotate ( 0 ) ;
} else {
if ( fa == fa->fa->ch[0] ) {
this == fa->ch[0] ? fa->Rotate ( 1 ) : Rotate ( 0 ) ;
Rotate ( 1 ) ;
} else {
this == fa->ch[1] ? fa->Rotate ( 0 ) : Rotate ( 1 ) ;
Rotate ( 0 ) ;
}
}
}
push_up () ;
}
void access()
{
Node* now = this ;
Node* x = null ;
while ( now != null )
{
now->splay () ;
now->link_child ( x , 1 ) ;
now->push_up () ;
x = now ;
now = now->fa ;
}
splay () ;
}
void make_root()
{
access();
update_rev();
}
void cut()
{
access();
ch[0]->fa = null;
ch[0] = null;
push_up();
}
Node* find_root ()
{
access () ;
Node* to = this ;
while ( to->ch[0] != null )
{
to->push_down () ;
to = to->ch[0] ;
}
return to ;
}
void cut(Node* to)
{
to->make_root();
cut();
}
void link(Node* to)
{
to->make_root();
to->fa = this;
}
void make_same(Node* to,int val)
{
to->make_root();
access();
update_same(val);
}
void make_add(Node* to,int val)
{
to->make_root();
access();
update_add(val);
}
void query(Node* to)
{
to->make_root();
access();
if(!max_num)
printf("ALL SAME\n");
else
printf("%d %d\n",sMax,max_num);
}
};
Node memory_pool[maxn];
Node* now;
Node* node[maxn];
void Clear()
{
now = memory_pool;
now->newnode(-INF);
null = now ++;
null->Size = 0;
}
int main()
{
int T,n,cas = 1,m;
int x,y,a,b,c;
int ob;
// freopen("in.txt","r",stdin);
scanf("%d",&T);
while(T--)
{
Clear();
scanf("%d%d",&n,&m);
printf("Case #%d:\n",cas++);
for(int i = 1; i <= n; i++)
{
scanf("%d",&x);
now->newnode(x);
node[i] = now++;
}
for(int i = 1; i < n; i++)
{
scanf("%d%d",&a,&b);
node[a]->link(node[b]);
}
for(int i= 1; i <= m; i++)
{
scanf("%d",&ob);
if(ob == 1)
{
scanf("%d%d%d%d",&x,&y,&a,&b);
node[x]->cut(node[y]);
node[a]->link(node[b]);
}
else if(ob == 2)
{
scanf("%d%d%d",&x,&y,&c);
node[x]->make_same(node[y],c);
}
else if(ob == 3)
{
scanf("%d%d%d",&x,&y,&c);
node[x]->make_add(node[y],c);
}
else if(ob == 4)
{
scanf("%d%d",&x,&y);
node[x]->query(node[y]);
}
}
}
return 0;
}
原文:http://www.cnblogs.com/Przz/p/5792203.html