bool hasSubTree(Bnode*parent,Bnode*son)
{
if(!son)
return tree;
if(!parent)
return false;
bool resul=false;
//都相等 退出
if(patent->val=son->val&&left)
else
resul=SubTree(patent->left,son);
else
result=SubTree(patent->right,son)
//
}
bool SubTree(Bnode*p1,Bnode*p2)
{
if(p1->val==p2->val)
}
原文：http://www.cnblogs.com/mmziscoming/p/5815503.html