<html>
<head>
</head>
<body>
<form action="7.php">
地址：<input type="text" name="addr" value="localhost">
用户：<input type="text" name="name" value="root">
密码：<input type="text" name="pass" value="root">
<input type="button" value="提交" onclick="a();">
</form>
<script src="js\jquery-1.11.2.min.js"></script>
<script>
function a(){
var cont=$("input").serialize();
$.ajax({
url:"7.php",
type:‘post‘,
data:cont,
success:function (data){
var res = eval("(" + data + ")");//转为Object对象
//用JQ来取值
// $.each(res,function(i,v){
// $.each(v,function(m,n){
// document.write(m+"-----"+n+"<br>");
// })
// })
//用for来取值
for (var i in res) {
for (var n in res[i]){
document.write(n+"-----"+res[i][n]+"<br>");
}
}
// document.write("Host:"+res[0]["Host"]+"<br>");
// document.write("User:"+res[0]["User"]+"<br>");
// document.write("Pass:"+res[0]["Password"]+"<br>");
}
})
}
</script>
</body>
</html>PHP页面
<?php
$name=$_POST["name"];
$pass=$_POST["pass"];
$addr=$_POST["addr"];
$conn=mysql_connect($addr,$name,$pass);
if (!$conn) {
die(‘Could not connect: ‘ . mysql_error());
}
mysql_select_db("mysql");
$str="select * from user;";
$result=mysql_query($str);
for ($i=0; $arr[$i]=mysql_fetch_assoc($result) ; $i++) ;
array_pop($arr);
$arr=json_encode($arr);
echo $arr;
mysql_close($conn);
?>原文：http://sr0517.blog.51cto.com/809286/1845625