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[LeetCode] 237. Delete Node in a Linked Lis解题小结

时间:2016-09-06 01:00:33      阅读:156      评论:0      收藏:0      [点我收藏+]

题目:

Write a function to delete a node (except the tail) in a singly linked list, given only access to that node.

Supposed the linked list is 1 -> 2 -> 3 -> 4 and you are given the third node with value 3, the linked list should become 1 -> 2 -> 4after calling your function.

首先判断这个结点是不是空结点或尾结点,然后要记得释放内存,以免造成memory leak

/**
 * Definition for singly-linked list.
 * struct ListNode {
 *     int val;
 *     ListNode *next;
 *     ListNode(int x) : val(x), next(NULL) {}
 * };
 */
class Solution {
public:
    void deleteNode(ListNode* node) {
        if(!node || !node->next) return;
        ListNode *delNode;
        delNode = node->next;
        node->val = node->next->val;
        node->next = node->next->next;
        free(delNode);
    }
};

 

[LeetCode] 237. Delete Node in a Linked Lis解题小结

原文:http://www.cnblogs.com/Doctengineer/p/5844120.html

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