Sicily 7970. Encoded Message 解题报告

 1 #include <iostream>
 2 #include <cmath>
 3 using namespace std;
 4 
 5 int main(){
 6     int testcases;
 7     cin >> testcases;
 8     while(testcases--){
 9         string message;
10         cin >> message;
11         int len = message.length();
12         int gap = sqrt(len);
13         for (int i = gap - 1; i >= 0; i--) {
14             for (int j = 0; j < gap; j++) {
15                 cout << message[i + j * gap];
16             }
17         }
18         cout << endl;
19     }
20     return 0;
21 }