题目：
Given a string s consists of upper/lower-case alphabets and empty space characters ‘ ‘, return the length of last word in the string.
If the last word does not exist, return 0.
Note: A word is defined as a character sequence consists of non-space characters only.
For example,
Given s = "Hello World",
return 5. （Easy）
分析：
注意把最后的空格处理掉即可。
代码：
1 class Solution { 2 public: 3 int lengthOfLastWord(string s) { 4 int start = s.size() - 1; 5 int result = 0; 6 while (s[start] == ‘ ‘) { 7 start--; 8 } 9 for (int i = start; i >= 0; --i) { 10 if (s[i] != ‘ ‘) { 11 result++; 12 } 13 else { 14 return result; 15 } 16 } 17 return result; 18 } 19 };
LeetCode58 Length of Last Word
原文：http://www.cnblogs.com/wangxiaobao/p/5886920.html