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[LeetCode] Convert a Number to Hexadecimal 数字转为十六进制

时间:2016-10-02 00:50:21      阅读:439      评论:0      收藏:0      [点我收藏+]

 

Given an integer, write an algorithm to convert it to hexadecimal. For negative integer, two’s complement method is used.

Note:

  1. All letters in hexadecimal (a-f) must be in lowercase.
  2. The hexadecimal string must not contain extra leading 0s. If the number is zero, it is represented by a single zero character ‘0‘; otherwise, the first character in the hexadecimal string will not be the zero character.
  3. The given number is guaranteed to fit within the range of a 32-bit signed integer.
  4. You must not use any method provided by the library which converts/formats the number to hex directly.

 

Example 1:

Input:
26

Output:
"1a"

 

Example 2:

Input:
-1

Output:
"ffffffff"

 

s

 

[LeetCode] Convert a Number to Hexadecimal 数字转为十六进制

原文:http://www.cnblogs.com/grandyang/p/5926674.html

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