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Linked List Cycle II

时间:2016-10-03 17:15:35      阅读:233      评论:0      收藏:0      [点我收藏+]

Given a linked list, return the node where the cycle begins. If there is no cycle, return null.

Note: Do not modify the linked list.

/**
 * Definition for singly-linked list.
 * struct ListNode {
 *     int val;
 *     ListNode *next;
 *     ListNode(int x) : val(x), next(NULL) {}
 * };
 */
class Solution {
public:
    ListNode *detectCycle(ListNode *head) {
        ListNode* slow = head;
        ListNode* fast = head;
        while(fast && fast->next){
            slow = slow->next;
            fast = fast->next->next;
            if(slow == fast){
                ListNode* slow2 = head;
                while(slow2 != slow){
                    slow = slow->next;
                    slow2 = slow2->next; 
                }
                return slow;
            }
        }
        return nullptr;
    }
};

 

Linked List Cycle II

原文:http://www.cnblogs.com/wxquare/p/5929262.html

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