模板题,找来测代码。
注意有相同单词
//#pragma comment(linker, "/STACK:1024000000,1024000000") #include<cstdio> #include<cstring> #include<cstdlib> #include<algorithm> #include<iostream> #include<sstream> #include<cmath> #include<climits> #include<string> #include<map> #include<queue> #include<vector> #include<stack> #include<set> using namespace std; typedef long long ll; typedef unsigned long long ull; typedef pair<int,int> pii; #define pb(a) push(a) #define INF 0x1f1f1f1f #define lson idx<<1,l,mid #define rson idx<<1|1,mid+1,r #define PI 3.1415926535898 template<class T> T min(const T& a, const T& b, const T& c) { return min(min(a, b), c); } template<class T> T max(const T& a, const T& b, const T& c) { return max(max(a, b), c); } void debug() { #ifdef ONLINE_JUDGE #else freopen("in.txt","r",stdin); // freopen("d:\\out1.txt","w",stdout); #endif } int getch() { int ch; while((ch = getchar()) != EOF) { if(ch!=‘ ‘ && ch!=‘\n‘) return ch; } return EOF; } const int max_len = 510; const int max_node = max_len * max_len; const int sigma_size = 26; struct ac_automation { int sz; int ch[max_node][sigma_size]; int fail[max_node]; vector<int> val[max_node]; int last[max_node]; void init() { memset(ch[0], 0, sizeof(ch[0])); val[0].clear(); sz = 1; } int id(char c) { return c - ‘a‘; } void insert(const char *s, int v) { int u = 0; for(int i = 0; s[i] != ‘\0‘; i++) { int v = id(s[i]); if(!ch[u][v]) { memset(ch[sz], 0, sizeof(ch[sz])); val[sz].clear(); ch[u][v] = sz++; } u = ch[u][v]; } val[u].push_back(v); } void construct() { queue<int> q; fail[0] = 0; for(int c = 0; c < sigma_size; c++) { int u = ch[0][c]; if(u) {q.push(u); fail[u] = 0; last[u] = 0; } } while(!q.empty()) { int r = q.front(); q.pop(); for(int c = 0; c < sigma_size; c++) { int u = ch[r][c]; if(u) { q.push(u); fail[u] = ch[fail[r]][c]; last[u] = (!val[fail[u]].empty()) ? fail[u] : last[fail[u]]; } else ch[r][c] = ch[fail[r]][c]; } } } void count(int x[], int u) { if(val[u].size() > 0) { for(int i = 0; i < val[u].size(); i++) x[val[u][i]]++; count(x, last[u]); } } void find(const char *T, int x[]) { int u = 0; for(int i = 0; T[i] != ‘\0‘; i++) { int v = id(T[i]); u = ch[u][v]; if(!val[u].empty()) count(x, u); else if(last[u]) count(x, last[u]); } } }; ac_automation solver; const int maxn = 1000100; char T[maxn]; int ans[maxn]; int main() { debug(); int t; scanf("%d", &t); for(int ca = 1; ca <= t; ca++) { solver.init(); int n; scanf("%d%s", &n, T); for(int i = 1; i <= n; i++) { char word[max_len]; scanf("%s", word); solver.insert(word, i); } solver.construct(); memset(ans, 0, sizeof(ans)); solver.find(T, ans); printf("Case %d:\n", ca); for(int i = 1; i <= n; i++) { printf("%d\n", ans[i]); } } return 0; }
lightoj 1427 - Substring Frequency (II) AC自动机,布布扣,bubuko.com
lightoj 1427 - Substring Frequency (II) AC自动机
原文:http://www.cnblogs.com/BMan/p/3726309.html