题目链接:
Time Limit: 3000/1500 MS (Java/Others) Memory Limit: 65536/65536 K (Java/Others)
Total Submission(s): 687 Accepted Submission(s): 262
#include <bits/stdc++.h>
using namespace std;
const int maxn=1e6+10;
int n,m,p,a[maxn],b[maxn],c[maxn],nex[maxn];
inline void makenext()
{
int k=-1,j=0;nex[0]=-1;
while(j<m)
{
if(k==-1||b[j]==b[k])
{
j++;k++;
nex[j]=k;
}
else k=nex[k];
}
}
inline int kmp(int l)
{
int pb=0,pc=0,ans=0;
while(pb<m&&pc<l)
{
if(pb==-1||b[pb]==c[pc])pb++,pc++;
else pb=nex[pb];
if(pb==m)ans++,pb=nex[pb];
}
return ans;
}
int main()
{
int t,Case=0;
scanf("%d",&t);
while(t--)
{
scanf("%d%d%d",&n,&m,&p);
for(int i=0;i<n;i++)scanf("%d",&a[i]);
for(int i=0;i<m;i++)scanf("%d",&b[i]);
makenext();
int ans=0;
for(int i=0;i<p;i++)
{
int cnt=0;
for(int j=i;j<n;j+=p)c[cnt++]=a[j];
ans+=kmp(cnt);
}
printf("Case #%d: %d\n",++Case,ans);
}
return 0;
}
原文:http://www.cnblogs.com/zhangchengc919/p/5939429.html