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Word Break

时间:2016-10-10 09:19:06      阅读:193      评论:0      收藏:0      [点我收藏+]

Given a string s and a dictionary of words dict, determine if s can be segmented into a space-separated sequence of one or more dictionary words.

For example, given
s = "leetcode",
dict = ["leet", "code"].

Return true because "leetcode" can be segmented as "leet code".

 

Analyse: Use dynamic programming to solve this problem. 

 1 class Solution {
 2 public:
 3     bool wordBreak(string s, unordered_set<string>& wordDict) {
 4         vector<bool> canDivide(s.size() + 1, false);
 5         canDivide[0] = true;
 6         
 7         for (int i = 0; i < s.size(); i++) {
 8             for (int j = i; j >= 0; j--) {
 9                 if (canDivide[i - j] && wordDict.find(s.substr(i - j, j + 1)) != wordDict.end()) {
10                     canDivide[i + 1] = true;
11                     break;
12                 }
13             }
14         }
15         return canDivide[s.size()];
16     }
17 };

 

Word Break

原文:http://www.cnblogs.com/amazingzoe/p/5944476.html

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