首页 > 其他 > 详细

Leetcode 线性表 Remove Duplicates from Sorted Array

时间:2014-05-15 06:57:37      阅读:328      评论:0      收藏:0      [点我收藏+]

本文为senlie原创,转载请保留此地址:http://blog.csdn.net/zhengsenlie


Remove Duplicates from Sorted Array

 Total Accepted: 14789 Total Submissions: 46601

Given a sorted array, remove the duplicates in place such that each element appear only once and return the new length.

Do not allocate extra space for another array, you must do this in place with constant memory.

For example,
Given input array A = [1,1,2],

Your function should return length = 2, and A is now [1,2].


题意:从一个已排序的数组中移除掉重复的元素
思路:用下标i扫描旧数组,用下标j来保存新数组的尾部
如果旧数组的当前元素与新数组的最后一个元素相同,则继续扫描旧数组
如果不同,新数组的下标前移一们,将旧数组的当前元素赋给新数组,继续扫描旧数组

相关题目:

Remove Element
Remove Duplicates from Sorted List
Remove Duplicates from Sorted List II
Remove Duplicates from Sorted Array II 
Remove Nth Node From End of List 


class Solution {
public:
    int removeDuplicates(int A[], int n) {
    	int j = 0;
    	for(int i = 1; i < n; i++){
    		if(A[i] != A[j]) A[++j] = A[i];
    	}
    	if(n == 0) return 0;
    	else return j + 1;
    }
};


Leetcode 线性表 Remove Duplicates from Sorted Array,布布扣,bubuko.com

Leetcode 线性表 Remove Duplicates from Sorted Array

原文:http://blog.csdn.net/zhengsenlie/article/details/25775113

(0)
(0)
   
举报
评论 一句话评论(0
关于我们 - 联系我们 - 留言反馈 - 联系我们:wmxa8@hotmail.com
© 2014 bubuko.com 版权所有
打开技术之扣,分享程序人生!